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0.15x^2-90x-2025=0
a = 0.15; b = -90; c = -2025;
Δ = b2-4ac
Δ = -902-4·0.15·(-2025)
Δ = 9315
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{9315}=\sqrt{81*115}=\sqrt{81}*\sqrt{115}=9\sqrt{115}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-90)-9\sqrt{115}}{2*0.15}=\frac{90-9\sqrt{115}}{0.3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-90)+9\sqrt{115}}{2*0.15}=\frac{90+9\sqrt{115}}{0.3} $
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